We will learn about how to open EXE file with JAVA. We use netbeans as IDE. So, please create new JAVA Application project. And a small form.

Step #1 Create few of label, combobox, and button from tool bar

I use few list item of combobox: Notepad, Window Explorer, Firefox, and Kalkulator as Target EXE

Step #2 Right click on Button to add action performed

Step #3 Use condition to select exe target

String target;
        String newTarget = null;
        target=(String) jComboBox1.getSelectedItem();
        if(target.equals("Notepad"))
        {
            newTarget = "C:\\Windows\\notepad.exe";
            jLabel3.setText(target + " EXECUTED!!");
        }
        else if(target.equals("Window Explorer"))
        {
            newTarget = "C:\\Windows\\explorer.exe";
            jLabel3.setText(target + " EXECUTED!!");
        }
        else if(target.equals("Firefox"))
        {
            newTarget = "C:\\Program Files\\Mozilla Firefox\\firefox.exe";
            jLabel3.setText(target + " EXECUTED!!");
        }
        else if(target.equals("Kalkulator"))
        {
            newTarget = "C:\\Windows\\System32\\calc.exe";
            jLabel3.setText(target + " EXECUTED!!");
        }
        else
        {
            jLabel3.setText("Silahkan Pilih Salah Satu TARGET EXE");
        }

        try
        {
            Process p = Runtime.getRuntime().exec(newTarget);
            p.waitFor();
            System.out.println(p.exitValue());
        }
        catch (Exception err)
        {
            err.printStackTrace();
        }

Step #4 Let’s RUN your application [F6]

That’s it!

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